Test. Modul+Progressiya ___________________________________(ism familiya) 1. 3. 17. Tengsizlikni yeching. |3−4|7−5|| B) 0,5 C) 1 A) 1 2. |4−5|4−6|+4|3−6|| Hisoblang. 2 D) 5 4 5 6 E) 1 √𝑥 2 + √𝑥 4 ≤ 4 1 5 Agar p>q>k>0 bo’lsa, |𝑝 + 𝑞| − |𝑘 − 𝑞| + |𝑘 − 𝑝| ni soddalashtiring. A) 2p B) 2p+2q-2k C) 2p=2q=2k D) 2p=2k E) 2q-2k Tenglamaning nechta yechimi bor? |x+1|=|2x-1| 4. A) 4 B) 3 C) 2 D) 1 E) ∅ Tenglamaning ildizlari yig’indisini toping. __________________________________________ |x+3|+|x-1|+|x-4|=6 A) ∅ B) 0 C) -4 D) 1 E) -2 5. Tenglamaning ildizlari yig’indisini toping. |x+4|+|x-2|+|x-3|=7 A) 2 B) ∅ C) 0 D) -2 E) 1 6. Tenglamaning nechta yechimi bor? 𝑥 2 + |𝑥| − 2 = 0 A) 0 B) 1 C) 2 D) 3 E) 4 7. Tengsizlikni yeching. |𝑥 − 1| ≥ 1 A) [0; 2] B) (−∞; 0] ∪ [2; ∞) C) [−2; 0] D) (0; 2) E) [−1; 2] 8. |𝑥 2 − 3𝑥| < 10 tengsizlikning butun sonlardan iborat yechimlari yig’indisini toping. A) 6 B) 7 C) 9 D) 12 E) 16 9. a ning qanday qiymatlarida 3|𝑥| + 𝑦 = 2 { sistema yagona yechimga ega ? |𝑥| + 2𝑦 = 𝑎 A) a=0 B) a>0 C) a=2 D) a=−2 E) a=4 10. Tenglama ildizlari ko’paytmasini toping. 4 √𝑥 2 + 77 − 2 √𝑥 2 + 77 − 3 = 0 A) -3 B) 3 C) 4 D) -4 E) -6 11. Tenglamani yeching. √5 − 4𝑥 + 5 = 4𝑥 A) 4 B) 5 5 C) 4 4 5 5 𝑣𝑎 4 D) − 4 E) − 5 5 4 12. Tenglamani yeching. 3 3 √𝑥 2 √𝑥 2 3√𝑥 2 … = 49 A) 49, -49 B) 7 C) 39 D) 50 E) 24 13. Agar √𝑥 + 3 − √𝑥 + 14 + √𝑥 + 3 + √𝑥 + 14 = 4 bo’lsa, A) 2 3 𝑥 𝑥+1 ning qiymatini hisoblang. B) − 2 3 C) 3 D) 3 2 E) − 3 2 14. Tenglamani yeching 3 3 √𝑥 + √𝑥 + 3√𝑥+. . . = 4 A) 56 B) 48 C) 60 D) 54 E) 64 15. Tengsizlikni yeching. √3𝑥 − 8 < −2 A) 𝑥 < 4 B) 𝑥 ∈ ∅ C) 𝑥 > 8 3 D) 𝑥 > 4 16. Tengsizlikni qanoatlantiruvchi butun sonlar nechta? A) 𝐴)(−∞; 2] B) [2; ∞) C) [−2; 2] D) [−2; ∞) E) [−1; 1] 18. Agar 𝑎1 + 𝑎3 +𝑎5 = −12 va 𝑎1 𝑎3 𝑎5 = 80 ekani ma’lum bo’lsa, arifmetik progressiyaning dastlabki uchta hadini toping. __________________________________________ 19. Yig’indisi 16 ga, ikkinchi hadi −0,5 ga teng bo’lgan |𝑞| < 1 maxrajli cheksiz geometrik progressiyaning 3-hadini toping. √5 − 𝑥 2 > 𝑥 − 1 5 B) 3 C) 4 D) 2 E) 1 20. 𝑥 4 − 10𝑥 2 + 𝑎 = 0 tenglamaning ildizlari arifmetik progressiyani tashkil etadi. 𝑎 ni toping. __________________________________________ 21. Agar 𝑎4 + 𝑎8 + 𝑎12 + 𝑎16 = 224 ekanligi ma’lum bo’lsa, 𝑎1 , 𝑎2 , 𝑎3 , … arifmetik progressiya dastlabki 19 ta hadining yig’indisini toping. __________________________________________ 22. Tenglamani yeching: 𝑥−1 𝑥−2 𝑥−3 1 + + +⋯+ = 3 𝑥 𝑥 𝑥 𝑥 bu yerda 𝑥 - musbat butun son. __________________________________________ 23. Yettiga bo’linadigan barcha uch xonali sonlarning yig’indisini toping. __________________________________________ 24. Yig’indini toping: 1 2 1 2 1 2 (2 + ) + (4 + ) + ⋯ + (2𝑛 + 𝑛 ) 2 4 2 __________________________________________ 25. 1- , 2- va oxirgi hadi, mos ravishda, 3, 12 va 3072 ga teng bo’lgan chekli geometrik progressiyaning hadlari sonini toping. __________________________________________ 26. 3 ga qoldiqsiz bo’linadigan barcha musbat juft ikki xonali sonlarning yig’indisini toping. __________________________________________ 27. Sayyoh tog’ga ko’tarilayotib, 1-soatda 800 m balandlikka chiqdi, keying har bir soatda esa oldingisiga nisbatan 25 m kam balandlikka ko’tarildi. U 5700 m balandlikka necha soatda ko’tarilgan? __________________________________________ 28. Arifmetik progressiya 3- va 9- hadlarining yig’indisi 8 ga teng. Shu progressiyaning dastlabki 11 ta hadining yigindisini toping. __________________________________________ 29. Hisoblang: (1 + 32 + 52 + ⋯ + (2𝑛 − 1)2 + ⋯ + 1992 ) − −(22 + 42 + 62 + ⋯ + (2𝑛)2 + ⋯ + 2002 ) __________________________________________ 𝑎 30. Biror arifmetik progressiyaga 2𝑛 = −1 bo’ladigan 𝑎2𝑚 𝑎2𝑛 va 𝑎2𝑚 hadlar kirishi ma’lum. Bu progressiyaning nolga teng hadi bormi? Agar bor bo’lsa, u progressiyaning nechanchi nomerli hadi bo’ladi? _________________________________________ 17 ta ochiq test va 13 ta yopiq test. Barcha javoblarni testga belgilaysilar. Kenjayev Asliddin