Образцы вариантов контрольных работ по курсу Физико

advertisement
 u(x1, x2 ) √
√ 2
u(x1 , x2 ) = (5 x1 + 2 x2 )
!"
# "
$"
% # &
' u(x1, x2 ) = x21 x32 () M = 30* p1 = 1* p2 = 2 +
)
1, * q1 = 3 - ./1"
#* /01* /11 $
−4
2 ( v(p, M) = M 7 p−3
1 p2 ) #
u(x1, x2)
3 ( u(x1, x2 ) = x31 x2 /(x2 + 3)4 ! ) 4
u(x1, x2 ) −2 −1
u(x1 , x2 ) = (8x−2
1 + 27x2 )
!"
# "
$"
% # &
' u(x1, x2 ) = x1 x42 () M = 40* p1 = 2* p2 = 1 +
)
2, * q2 = 4 - ./2"
#* /02* /12 5
3/4
2 ( & m(p, u) = u1/2p1/4
) # 1 p2
u(x1 , x2 )
3 ( u(x1, x2 ) = x1 − 4/x2 ,
! ) 4
1 −2 −1/2
f (x1 , x2 ) = (2x−2
1 + 3x2 )
!) 6 4
%6
7"
6
7
' 1 3/2 1/4
f (x1 , x2 ) = x1 x2
!) 6 4 Q 4& 7& C 86
) 4 2 1 f (x) = (x1 − 1)2 (x2 − 4)5 ,
x1 ≥ 1, x2 ≥ 4
86
) 4 2 +7 C = 2Q3 + 10 Q > 0 C = 5 Q = 0 )
4
4 4 1 −2 −1/2
f (x1 , x2 ) = (x−2
1 + 4x2 )
!) 6 4
%6
7"
6
7
' 1 2/3 1/4
f (x1 , x2 ) = x1 x2
!) 6 7 C 4 Q 8,
6
) 7 4
2 1 f (x) = (x1 + 1)3 (x2 − 5),
x1 ≥ 0, x2 ≥ 5
86
) 4 3 +7 C = 3Q2 + 5 Q > 0 C = 1 Q = 0 )
4
4 4 '
Download