531/534:[57+61] . . , . . A.A. Zaborskikh, V.M. Tverier Perm National Research Polytechnic University DEVELOPMENT OF MATHEMATICAL DESCRIPTION OF THE INTENAL STRUCTURE OF CANCELLOUS BONE . , . ; (fabric tensor). , . : , ( , ) , , , . Consideration of structural features of the dentofacial system units is one of the main problems of contemporary dental biomechanics. Heterogeneity of spongy structure can be described by methods of quantitative stereology. At the same time, structural bone tissue features are described by means of the fabric tensor . The measuring procedure for stereological investigations is analyzed. Properties of fabric tensor by constructing it for a sample of cancellous bone, carved out of the femoral head of human was investigated. Keywords: biomechanical modelling, Wolff’s law, bone tissue structure, cancellous bone tissue, fabric tensor, ellipse structure. 200 , 158 , . (substantia compacta) . (substantia spongiosa) , , - . . , , - [1]. . , [2]. , , , , , , . - , , , , , - . ( ) . . - : , [2]. . . - , , , [3–9]. , - , , [10–12]. . - Image Tool . . : . ( L. ) . L - . . Underwood [6], – 159 , . L ( . 1. - L , ( . 1). Ab. I( ). – – . [13] , ; , – ) - L b ( θ ) = 2 ∑ AAb , I ( θ) l l– – , Lb( ) ; ; I( ) – Ab – . - Lb( ), . - 2 1 mαα + mββ mαα − mββ + cos 2θ + mαβ sin 2θ, = L θ 2 2 ( ) b g Harrigan ( , . (1). Mann , ) : !) eg e , 1984 . [14], , 2 1 = n ⋅ M ⋅ n, L b ( θ) 160 (1) , - ( Lb - n– – - n = cos θeα + sin θeβ , , . : mgg, m , mg , m11 M = m12 m13 m13 m23 . m33 m12 m22 m23 Whitehouse (1974) [15], Harrigan , [18]. [17] Mann (1984) [16], Turner (1987) , , [12] . ( Lb( ) - ) . 1986 . Cowin , , . , : ( ) 1 2 = M −1 . , H , , . . R def α= mαα + mββ 2 def , β= mαα − mββ 2 def , γ =mαβ , 1 2 α+c R= . α−c 161 , , mαα M = mαβ ) mgg, m Lb( ) mαβ . mββ M ( , (1) mg [19]. (1) f( ), - , 2 1 f ( θ) = . L b ( θ ) . : def - def f l = f ( θl ) , ψ l = 2θl , l = 1, 2, 3, fl – - l. mgg, m mg - : mαα = f 2 (1 − cos ψ1 ) − f1 (1 − cos ψ 2 ) ψ + ψ2 + κ ctg 1 (1 − cos ψ1 ) − sin ψ1 , (2) cos ψ 2 − cos ψ1 2 mββ = f1 (1 + cos ψ 2 ) − f 2 (1 + cos ψ1 ) ψ + ψ2 − κ ctg 1 (1 + cos ψ1 ) + sin ψ1 , (3) cos ψ 2 − cos ψ1 2 mαβ = κ. , def κ= k– , : 162 (4) , f 3 − k ⋅ f 2 + f1 ( k − 1) , sin ψ 3 − k ⋅ sin ψ 2 + sin ψ1 ( k − 1) - cos ψ 3 − cos ψ1 . cos ψ 2 − cos ψ1 def k= sin ( ψ1 − ψ 2 ) + sin ( ψ 2 − ψ 3 ) + sin ( ψ 3 − ψ1 ) ≠ 0. 2 f1 f 2 f 3 : , 1 = 0°, 2 = 120° 3 = 240°. (2)–(4) : mαα = f1 , mββ = 1 ( 2 ⋅ ( f 2 + f3 ) − f1 ) , 3 3 ( f3 − f 2 ) , 3 mαβ = k = 1. f1 > 0, ( ) 2 ( f1 f 2 + f 2 f3 + f1 f3 ) > f12 + f 22 + f32 . ( , ), - , [20]. , ( , , . . ) = H (d, N, d, N , – ( , ) - ), , . , - . 163 , . [21] ( . 2). - 600 ° 4 . - Image Tool. ( . 3). , . . 2. [22] ( ( . 3. 164 - . 5). . 4. . 4), - . 5. – ; – ; – ; : – – ; 165 , , - . , , . – . . - , . , - [23–25]. 1. : . 1 / . . .– : , 1973. – 315 . 2. 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